SIMULATION TOOLS IN SYSTEM DESIGN
19
fundamental frequency. All input frequencies of the system must be an
integer multiple of the fundamental frequency. The methods of computing
the steady state solution are different in PSS and HB.
Figure 3-2. Results of a PSS analysis of an LNA
Figure 3-2 shows the results of a PSS analysis in frequency (left hand
graphs) and time domain (right hand graphs). The input signal was two-tone
with 850 and 900 MHz, each with a -10 dBm magnitude (upper graphs).
Each input frequency must be an integer multiple of the fundamental
frequency. Thus a fundamental frequency of 50 MHz is used in the example.
This is equivalent to a period of 20 ns. To visualize frequencies up to 2 GHz,
40 harmonics of the fundamental frequency were computed. The time
domain output of the LNA (bottom right hand graph) shows that the LNA is
operated in the nonlinear area. The 3rd order harmonics at 800 MHz and
950 MHz are visible in the frequency domain (upper left hand graph). Other
analyses are based on the steady state operating point, for example:
periodic AC analysis
periodic noise analysis
periodic XF (periodic transfer function)
periodic SP (periodic S-parameters)
Summary :
Results of a PSS analysis of an LNA Figure 3-2 shows the results of a PSS analysis in frequency (left hand graphs) and time domain (right hand graphs). Other analyses are based on the steady state operating point, for example: periodic AC analysis periodic noise analysis periodic XF (periodic transfer function) periodic SP (periodic S-parameters)
Tags :
frequency,periodic,fundamental,hand,mhz,analysis,domain,input,lna,graphs,pss,left,shows